document.write( "Question 288682: A sample of 900 observations taken from a population produced a sample proportion of 0.32. Make a 90% confidence interval for p. Round the answers to 3 decimal places. \n" ); document.write( "
Algebra.Com's Answer #209217 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A sample of 900 observations taken from a population produced a sample proportion of 0.32. \n" ); document.write( "Make a 90% confidence interval for p. Round the answers to 3 decimal places. \n" ); document.write( "----------- \n" ); document.write( "standard error: 1.645*sqrt[0.32*0.68/900] = 0.026 \n" ); document.write( "----------------------------------- \n" ); document.write( "90% CI: 0.32-0.026 < p < 0.32+0.026 \n" ); document.write( "90% CI: 0.294 < p < 0.346 \n" ); document.write( "============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |