document.write( "Question 4557: Solve problem exactly\r
\n" ); document.write( "\n" ); document.write( "log 8 - log x = 2
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Algebra.Com's Answer #2092 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Again, I am assuming that \"log\" refers to log \"base 10.\" \r
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\n" ); document.write( "\n" ); document.write( "\"log+%2810%2C+8%29+-+log+%2810%2C+x%29+=+2\"
\n" ); document.write( "\"log+%2810%2C+%288%2Fx%29%29+=+2\"\r
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\n" ); document.write( "Translate back into exponential notation:
\n" ); document.write( "\"10%5E2+=+8%2Fx+\"\r
\n" ); document.write( "\n" ); document.write( "\"100+=+8%2Fx\"\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by x:\r
\n" ); document.write( "\n" ); document.write( "\"100x+=+8\"\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by 100:
\n" ); document.write( "\"x+=+8%2F100\" = \"2%2F25+\" or 0.08\r
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\n" ); document.write( "\n" ); document.write( "You can check by substituting the value of x=0.08 into a calculator. Surprise--it works!!\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC\r
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