document.write( "Question 288613: If remainder of (5m+1)(5m+3)(5m+4)/5 is a natural number then find the remainder. \n" ); document.write( "
Algebra.Com's Answer #209187 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"%28%285m%2B1%29%285m%2B3%29%285m%2B4%29%29%2F5\"\r\n" );
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document.write( "\"%28%2825m%5E2%2B20m%2B3%29%285m%2B4%29%29%2F5\"\r\n" );
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document.write( "\"%28125m%5E3%2B100m%5E2%2B100m%5E2%2B80m%2B15m%2B12%29%2F5\"\r\n" );
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document.write( "\"%28125m%5E3%2B200m%5E2%2B95m%2B12%29%2F5\"\r\n" );
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document.write( "\"25m%5E3%2F5%2B200m%5E2%2F5%2B95m%2F5%2B12%2F5\"\r\n" );
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document.write( "\"5m%5E3%2B40m%5E2%2B19m%2B12%2F5\"\r\n" );
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document.write( "Write the 12 as 10+2\r\n" );
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document.write( "\"5m%5E3%2B40m%5E2%2B19m%2B%2810%2B2%29%2F5\"\r\n" );
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document.write( "\"5m%5E3%2B40m%5E2%2B19m%2B10%2F5%2B2%2F5\"\r\n" );
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document.write( "\"5m%5E3%2B40m%5E2%2B19m%2B2%2B2%2F5\"\r\n" );
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document.write( "So the fraction part when dividing by 5 was \"2%2F5\" so the\r\n" );
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document.write( "remainder had to be 2\r\n" );
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document.write( "Edwin
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