document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=288567>Question 288567</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a sample of 80 car owners revealed that 24 owned station wagons and 62 owned cars which are not station wagons find the number k of people who owned both a station wagon and some other car?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #209157 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=209157\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have 80 car owners in total.<BR>\n" );
document.write( "24 owned station wagons.<BR>\n" );
document.write( "62 owned cars which are not station wagons.<BR>\n" );
document.write( "How many owned both a station wagon and a car.\r<BR>\n" );
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document.write( "24 + 62 = 86.\r<BR>\n" );
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document.write( "There are 86 cars and only 80 owners.\r<BR>\n" );
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document.write( "Assuming a maximum of 2 cars per owner, then the number of people who owned a car and a station wagon would be 6 I think.\r<BR>\n" );
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document.write( "If we have 6 people owning a car and a station wagon, then we have:\r<BR>\n" );
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document.write( "24 - 6 = 18 owned a station wagon only.<BR>\n" );
document.write( "62 - 6 = 56 owned a car only.<BR>\n" );
document.write( "6 owned a car and a station wagon.\r<BR>\n" );
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document.write( "That's a total of 18 + 56 + 6 = 80 people who either owned a car or a station wagon or a car and a station wagon.\r<BR>\n" );
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document.write( "That's a total of (18 * 1) + (56 * 1) + (6 * 2) cars = 18 + 56 + 12 = a total of 86 cars.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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