document.write( "Question 288539: The perimiter of a rectangle is 150 inches. The length exceeds the width by 29 inches. Find the length and width. \n" ); document.write( "
Algebra.Com's Answer #209142 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let the with be x\r \n" ); document.write( "\n" ); document.write( "the length = x+29\r \n" ); document.write( "\n" ); document.write( "perimeter = 2x + 2(x+29) = 150\r \n" ); document.write( "\n" ); document.write( "2x+2x+58=150\r \n" ); document.write( "\n" ); document.write( "4x=150-58\r \n" ); document.write( "\n" ); document.write( "4x=92 \n" ); document.write( "x= 23 thw width\r \n" ); document.write( "\n" ); document.write( "length = 23 +29 = 52\r \n" ); document.write( "\n" ); document.write( "52+52+23+23= 150\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |