document.write( "Question 288541: A motorboat takes 4 hours to travel 256 mi going upstream. The return trip takes 2 hours going downstream. What is the rate of the boat in still water and what is the rate of the current? \n" ); document.write( "
Algebra.Com's Answer #209140 by mananth(16946)\"\" \"About 
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A motorboat takes 4 hours to travel 256 mi going upstream. The return trip takes 2 hours going downstream. What is the rate of the boat in still water and what is the rate of the current?\r
\n" ); document.write( "\n" ); document.write( "let speed of the boat in still water be x\r
\n" ); document.write( "\n" ); document.write( "let the speed of the current be y\r
\n" ); document.write( "\n" ); document.write( "upstream speed of boat is x-y\r
\n" ); document.write( "\n" ); document.write( "distance is 256\r
\n" ); document.write( "\n" ); document.write( "time is 4 hours\r
\n" ); document.write( "\n" ); document.write( "256 / x-y =4\r
\n" ); document.write( "\n" ); document.write( "Down stream\r
\n" ); document.write( "\n" ); document.write( "speed of boat = x+y\r
\n" ); document.write( "\n" ); document.write( "distance = 256\r
\n" ); document.write( "\n" ); document.write( "256/ x+y = 2\r
\n" ); document.write( "\n" ); document.write( "4x-4y=256------------1\r
\n" ); document.write( "\n" ); document.write( "2x+2y=256------------2\r
\n" ); document.write( "\n" ); document.write( "multiply eq 2 by 2\r
\n" ); document.write( "\n" ); document.write( "4x+4y=512-----------3\r
\n" ); document.write( "\n" ); document.write( "Add eq 1 & 3\r
\n" ); document.write( "\n" ); document.write( "4x-4y+4x+4y=512+512\r
\n" ); document.write( "\n" ); document.write( "8x=1024\r
\n" ); document.write( "\n" ); document.write( "x= 1024/8\r
\n" ); document.write( "\n" ); document.write( "=128 mph\r
\n" ); document.write( "\n" ); document.write( "plug the value of x in eq1\r
\n" ); document.write( "\n" ); document.write( "we get y=64mph speed of the current\r
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