document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34642>Question 34642</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve by addtion method 5x-4y=-5<BR>\n" );
document.write( "                        x-2y=-7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20913 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20913\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5X-4Y=-5<BR>\n" );
document.write( "X-2Y=-7   MULTIPLY THE SECOND EQUATION BY -2 WE GET \r<BR>\n" );
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document.write( "-2X+4Y=+14 TO WHICH WE ADD EQUATION ONE <BR>\n" );
document.write( "5X-4Y=-5<BR>\n" );
document.write( "--------- WE GET<BR>\n" );
document.write( "3X=9 OR X=9/3 OR X=3 \r<BR>\n" );
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document.write( "SUBSTITUTING 3 FOR X IN EQUATION ONE WE GET\r<BR>\n" );
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document.write( "5*3-4Y=-5 OR 15-4Y=-5 OR -4Y=-20 OR 4Y=20 OR Y=20/4 OR Y=5\r<BR>\n" );
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document.write( "PROOF 3-2*5=-7 OR 3-10=-7 OR -7=-7<BR>\n" );
document.write( " </SPAN>\n" );
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