document.write( "Question 288409: Using only the information that \"+log%28+10%2C+20+%29+\"=A and \"+log%28+10%2C+27+%29+\"=B show how to find log[160,000/3] in terms of A and B \n" ); document.write( "
Algebra.Com's Answer #209126 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Using only the information that \"+log%28+10%2C+20+%29+\"=A and \"+log%28+10%2C+27+%29+\"=B show how to find log[160,000/3] in terms of A and B
\n" ); document.write( "--------------
\n" ); document.write( "160000 = 20^4
\n" ); document.write( "3 = 27^(1/3)
\n" ); document.write( "--------------
\n" ); document.write( "log[160,000/3] = 4A - (B/3)
\n" ); document.write( "
\n" ); document.write( "
\n" );