document.write( "Question 288473: a man has 20 coins consisting of dimes and quarters. if the dimes were quarters and the quarters were dimes, he would have ninety cents more than he has now. how many dimes and quarters does he have? \n" ); document.write( "
Algebra.Com's Answer #209102 by ankor@dixie-net.com(22740)\"\" \"About 
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a man has 20 coins consisting of dimes and quarters.
\n" ); document.write( " if the dimes were quarters and the quarters were dimes,
\n" ); document.write( " he would have ninety cents more than he has now.
\n" ); document.write( "how many dimes and quarters does he have?
\n" ); document.write( ":
\n" ); document.write( "let x = original number of dimes
\n" ); document.write( "let y = original number of quarters
\n" ); document.write( ":
\n" ); document.write( "total coin equation
\n" ); document.write( "x + y = 20
\n" ); document.write( "y = (20-x); use for substitution
\n" ); document.write( ":
\n" ); document.write( "\"if the dimes were quarters and the quarters were dimes,
\n" ); document.write( " he would have ninety cents more than he has now.\"
\n" ); document.write( ":
\n" ); document.write( "Amt now = amt when reversed - .90
\n" ); document.write( ".10x + .25y = .10y + .25x - .90
\n" ); document.write( ".25y - 10y = .25x - .10x - 90
\n" ); document.write( ".15y = .15x - .90
\n" ); document.write( "Replace y with (20-x)
\n" ); document.write( ".15(20-x) = .15x - .90
\n" ); document.write( "3.00 - .15x = .15x - .90
\n" ); document.write( "3.00 + .90 = .15x + .15x
\n" ); document.write( "3.90 = .30x
\n" ); document.write( "x = \"3.9%2F.3\"
\n" ); document.write( "x = 13 dimes
\n" ); document.write( "then
\n" ); document.write( "y = 20-13 = 7 quarters
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution by finding the values
\n" ); document.write( "reversed: 7(.10) + 13(.25) = 3.95
\n" ); document.write( "original: 13(.10) + 7(.25) = 3.05
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\n" ); document.write( "difference: .90\r
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