document.write( "Question 288399: the sum of three numbers is 14.the sum of twice the first number,5 times the second number,and 6 times the third number is 72.the difference between 5 times the first number and the second number is 6.find the three numbers \n" ); document.write( "
Algebra.Com's Answer #209069 by ankor@dixie-net.com(22740)\"\" \"About 
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the sum of three numbers is 14.
\n" ); document.write( "the sum of twice the first number, 5 times the second number, and 6 times the
\n" ); document.write( "third number is 72.
\n" ); document.write( "the difference between 5 times the first number and the second number is 6.
\n" ); document.write( "find the three numbers
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\n" ); document.write( "Three numbers, x, y, z
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\n" ); document.write( "Write an equation for each statement:
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\n" ); document.write( "\"the sum of three numbers is 14.\"
\n" ); document.write( "x + y + z = 14
\n" ); document.write( ":
\n" ); document.write( "\"the sum of twice the first number, 5 times the second number,and 6 times the
\n" ); document.write( " third number is 72.\"
\n" ); document.write( "2x + 5y + 6z = 72
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\n" ); document.write( "\"the difference between 5 times the first number and the second number is 6.\"
\n" ); document.write( "5x - y = 6
\n" ); document.write( "y = (5x-6); use this for substitution
\n" ); document.write( ":
\n" ); document.write( "Add 5x - y to the 1st equation
\n" ); document.write( "x + y + z = 14
\n" ); document.write( "5x- y + 0 = 6
\n" ); document.write( "----------------- eliminates y
\n" ); document.write( "6x + z = 20
\n" ); document.write( "z = (20-6x); use this for substitution
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\n" ); document.write( "Substitute in 2x + 5y + 6z = 72
\n" ); document.write( "2x + 5(5x-6) + 6(20-6x) = 72
\n" ); document.write( "2x + 25x- 30 + 120 - 36x = 72
\n" ); document.write( "2x + 25x - 36x - 30 + 120 = 72
\n" ); document.write( "-9x + 90 = 72
\n" ); document.write( "-9x = 72 - 90
\n" ); document.write( "-9x = -18
\n" ); document.write( "x = +2
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\n" ); document.write( "I'll let you find y and z, check your solution in the 1st equation\r
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