document.write( "Question 288373: A fence is to be built to enclose a rectangular area of 290 square feet. The fence along three sides is to be made of material that costs 4 dollars per foot, and the material for the fourth side costs 15 dollars per foot. Find the length L and width W (with W \leq L) of the enclosure that is most economical to construct.
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Algebra.Com's Answer #209065 by ankor@dixie-net.com(22740)\"\" \"About 
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A fence is to be built to enclose a rectangular area of 290 square feet.
\n" ); document.write( " The fence along three sides is to be made of material that costs 4 dollars per foot,
\n" ); document.write( "and the material for the fourth side costs 15 dollars per foot.
\n" ); document.write( " Find the length L and width W (with W \leq L) of the enclosure that is most economical to construct.
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\n" ); document.write( "Area equation:
\n" ); document.write( "L * W = 290
\n" ); document.write( "W = \"290%2FL\"
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\n" ); document.write( "Perimeter equation
\n" ); document.write( "P = 2L + 2W
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\n" ); document.write( "Cost to enclose
\n" ); document.write( "C = 4(2L) + 4W + 15W
\n" ); document.write( "C = 8L + 19W
\n" ); document.write( "Replace W with \"%28290%2FL%29\"
\n" ); document.write( "C = 8L + 19\"%28290%2FL%29\"
\n" ); document.write( "C = 8L + \"5510%2FL\"
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\n" ); document.write( "Plot this equation, L is on the x axis, Cost on the y axis
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-10%2C+40%2C+-200%2C+1000%2C+8x%2B%285510%2Fx%29%29+\"
\n" ); document.write( "Minimum cost when L = 26 ft
\n" ); document.write( "then
\n" ); document.write( "\"290%2F26\" ~ 11.15 ft is the width
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\n" ); document.write( "Check area: 26 * 11.15 = 289.9 ~ 290
\n" ); document.write( "Check cost: 4(2*26) + 4(11.15) + 15(11.15) = $419.85 is minimum cost
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