document.write( "Question 288373: A fence is to be built to enclose a rectangular area of 290 square feet. The fence along three sides is to be made of material that costs 4 dollars per foot, and the material for the fourth side costs 15 dollars per foot. Find the length L and width W (with W \leq L) of the enclosure that is most economical to construct.
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #209065 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A fence is to be built to enclose a rectangular area of 290 square feet. \n" ); document.write( " The fence along three sides is to be made of material that costs 4 dollars per foot, \n" ); document.write( "and the material for the fourth side costs 15 dollars per foot. \n" ); document.write( " Find the length L and width W (with W \leq L) of the enclosure that is most economical to construct. \n" ); document.write( ": \n" ); document.write( "Area equation: \n" ); document.write( "L * W = 290 \n" ); document.write( "W = \n" ); document.write( ": \n" ); document.write( "Perimeter equation \n" ); document.write( "P = 2L + 2W \n" ); document.write( ": \n" ); document.write( "Cost to enclose \n" ); document.write( "C = 4(2L) + 4W + 15W \n" ); document.write( "C = 8L + 19W \n" ); document.write( "Replace W with \n" ); document.write( "C = 8L + 19 \n" ); document.write( "C = 8L + \n" ); document.write( ": \n" ); document.write( "Plot this equation, L is on the x axis, Cost on the y axis \n" ); document.write( " \n" ); document.write( "Minimum cost when L = 26 ft \n" ); document.write( "then \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Check area: 26 * 11.15 = 289.9 ~ 290 \n" ); document.write( "Check cost: 4(2*26) + 4(11.15) + 15(11.15) = $419.85 is minimum cost \n" ); document.write( " \n" ); document.write( " |