document.write( "Question 23901: Here is my question please help...\r
\n" ); document.write( "\n" ); document.write( "A research study on the calorie intake of 2300 women found that the mean calorie intake was 1650 calories per day. The data were normally distributed with a standard deviation of 175 calories. How many women in the study at between 1300 and 2000 calories a day?\r
\n" ); document.write( "\n" ); document.write( "Thats all i have no idea how to find the anwser so some help would be nice. Thanks
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Algebra.Com's Answer #20905 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Draw the normal curve putting 1650 at the mean; sigma=175 and
\n" ); document.write( "label the horizontal axis as \"x\".
\n" ); document.write( "You want to find Prob(1300\n" ); document.write( "Either use a TI-83 calculator to find this directly
\n" ); document.write( "or convert the 1300 and the 2000 to \"z-scores\", as follows:
\n" ); document.write( "z(1300)=[1300=1650]/175= -2
\n" ); document.write( "z(2000)=[2000-1650]/175= +2
\n" ); document.write( "Now your problem becomes Prob(-1\n" ); document.write( "Use your z-chart to find Prob(0\n" ); document.write( "I get an answer of 2*0.47725=0.9545~ 95.5%
\n" ); document.write( "So the Probability you are looking for is approx. 95.5%
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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