document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=288378>Question 288378</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A substance decomposes radioactively. It's half-life is 26 years. How much of the original substance will remain after 300 years? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #209036 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=209036\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A substance decomposes radioactively. <BR>\n" );
document.write( "It's half-life is 26 years. How much of the original substance will remain after 300 years?<BR>\n" );
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document.write( "The half life formula: A = Ao[2^(-t/h)]<BR>\n" );
document.write( "Where <BR>\n" );
document.write( "A = the resulting amt after t yrs<BR>\n" );
document.write( "Ao = initial amt<BR>\n" );
document.write( "t = time in yrs<BR>\n" );
document.write( "h = half-life in yrs<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Assume the initial amt = 1<BR>\n" );
document.write( "A = 2^(-300/26)<BR>\n" );
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document.write( "enter 2^(-300/26), on a good calc;<BR>\n" );
document.write( "A = .00033618 ~ .03362% after 300 years<BR>\n" );
document.write( " </SPAN>\n" );
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