document.write( "Question 288357: Find the value of x.
\n" ); document.write( "x%=x+6/200
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Algebra.Com's Answer #209029 by Alan3354(69443)\"\" \"About 
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x%=x+6/200
\n" ); document.write( "I suppose x% is x/100
\n" ); document.write( "x/100=x+6/200
\n" ); document.write( "Multiply thru by 200
\n" ); document.write( "2x = 200x + 6
\n" ); document.write( "-198x = 6
\n" ); document.write( "x = -1/33\r
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