document.write( "Question 288343: express as a single logarithm:
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Algebra.Com's Answer #209020 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
Your expression is:\r
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\n" ); document.write( "\n" ); document.write( "\"log%286%2C18%29+%2B+log%286%2C48%29+-+2%2Alog%286%2C2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Since, in general, \"x%2Alog%28y%29+=+log%28y%5Ex%29\", then:\r
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\n" ); document.write( "\n" ); document.write( "\"log%286%2C18%29+%2B+log%286%2C48%29+-+2%2Alog%286%2C2%29\" = \"log%286%2C18%29+%2B+log%286%2C48%29+-+log%286%2C2%5E2%29\" which becomes:\r
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\n" ); document.write( "\n" ); document.write( "\"log%286%2C18%29+%2B+log%286%2C48%29+-+log%286%2C4%29\"\r
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\n" ); document.write( "\n" ); document.write( "Since, in general, \"log%28x%29+-+log%28y%29+=+log%28x%2Fy%29\", then:\r
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\n" ); document.write( "\n" ); document.write( "\"log%286%2C18%29+%2B+log%286%2C48%29+-+log%286%2C4%29\" = \"log%286%2C18%29+%2B+log%286%2C%2848%2F4%29%29\" which becomes:\r
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\n" ); document.write( "\n" ); document.write( "\"log%286%2C18%29+%2B+log%286%2C%2812%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Since, in general, \"log%28x%29+%2B+log%28y%29+=+log%28x%2Ay%29\", then:\r
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\n" ); document.write( "\n" ); document.write( "\"log%286%2C18%29+%2B+log%286%2C%2812%29%29\" = \"log%286%2C%2818%2A12%29%29\" which becomes:\r
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\n" ); document.write( "\n" ); document.write( "\"log%286%2C216%29\".\r
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\n" ); document.write( "\n" ); document.write( "That's your answer:\r
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\n" ); document.write( "\n" ); document.write( "\"log%286%2C18%29+%2B+log%286%2C48%29+-+2%2Alog%286%2C2%29\" = \"log%286%2C216%29\".\r
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\n" ); document.write( "\n" ); document.write( "The original expression has been confirmed to be equivalent to the final expression.\r
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\n" ); document.write( "\n" ); document.write( "You can check this yourself by using the log function of your calculator.\r
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\n" ); document.write( "\n" ); document.write( "The conversion formula to use is that, in general, \"log%286%2Cx%29+=+log%2810%2Cx%29%2Flog%2810%2C6%29\".\r
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\n" ); document.write( "\n" ); document.write( "I will do the original expression for you and then you can do the final expression.\r
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\n" ); document.write( "\n" ); document.write( "The original expression is:\r
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\n" ); document.write( "\n" ); document.write( "\"log%286%2C18%29+%2B+log%286%2C48%29+-+2%2Alog%286%2C2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%286%2C18%29+=+log%2810%2C18%29%2Flog%2810%2C6%29+=+1.255272505%2F.77815125+=+1.613147193\".\r
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\n" ); document.write( "\n" ); document.write( "\"log%286%2C48%29+=+log%2810%2C48%29%2Flog%2810%2C6%29+=+1.681241237%2F.77815125+=+2.160558422\".\r
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\n" ); document.write( "\n" ); document.write( "Plug these values into the original expression equation and you get:\r
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\n" ); document.write( "\n" ); document.write( "\"log%286%2C18%29+%2B+log%286%2C48%29+-+2%2Alog%286%2C2%29\" = 1.613147193 + 2.160558422 - .773705614 = 3.\r
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\n" ); document.write( "\n" ); document.write( "When you confirm the final expression of \"log%286%2C216%29\", you should also get 3.\r
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\n" ); document.write( "\n" ); document.write( "You can convert the log base 6 to log base 10 using the conversion formula shown below:\r
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\n" ); document.write( "\n" ); document.write( "Log base 10 is found by using the LOG function of your calculator.\r
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\n" ); document.write( "\n" ); document.write( "\"log%286%2C216%29\" = \"log%2810%2C216%29%2Flog%2810%2C6%29\".\r
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