document.write( "Question 287786: a certain amount of money is invested at 8% and PHP150,000 more than that amount is invested at 9%. The annual interest from the 9% investment exceeds the annual interest from 8% investment by PHP16,00. How much is invested at 9%?\r
\n" ); document.write( "\n" ); document.write( "thankyou tutor..:)))
\n" ); document.write( "

Algebra.Com's Answer #209011 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
a certain amount of money is invested at 8%
\n" ); document.write( " and PHP150,000 more than that amount is invested at 9%.
\n" ); document.write( " The annual interest from the 9% investment exceeds the annual interest from 8% investment by PHP16,000.
\n" ); document.write( "How much is invested at 9%?
\n" ); document.write( ":
\n" ); document.write( "Not sure what PHP is but assume it will make no difference in the problem
\n" ); document.write( "Assume this is based on 1 yr
\n" ); document.write( ":
\n" ); document.write( "Let x = amt invested at 9%
\n" ); document.write( "then
\n" ); document.write( "(x-150000) = amt invested at 8%
\n" ); document.write( ":
\n" ); document.write( "Use the decimal form of the interest rates
\n" ); document.write( ":
\n" ); document.write( "Int at 9% - int at 8% = 16000
\n" ); document.write( ".09x - .08(x - 150000) = 16000
\n" ); document.write( ":
\n" ); document.write( ".09x - .08x + 12000 = 16000
\n" ); document.write( ":
\n" ); document.write( ".01x = 16000 - 12000
\n" ); document.write( "x = \"4000%2F.01\"
\n" ); document.write( "x = 400,000 invested at 9%
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution by finding the interest at each rate
\n" ); document.write( ".09(400000) = 36000
\n" ); document.write( ".08(400000-150000) = 20000
\n" ); document.write( "----------------------------
\n" ); document.write( "a difference of 16000
\n" ); document.write( "
\n" );