document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34609>Question 34609</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321279085/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> 3)	Use the geometric sequence of numbers 1, 1/2, 1/4, 1/8,…to find the following:<BR>\n" );
document.write( "a)	What is r, the ratio between 2 consecutive terms? <BR>\n" );
document.write( "Answer:	1/2<BR>\n" );
document.write( "Show work in this space.       r=(1/2/1=1/4/1/2)<BR>\n" );
document.write( "                                               r=1/2\r<BR>\n" );
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document.write( "b)	Using the formula for the sum of the first n terms of a geometric series, what is the sum of the first 10 terms? Please round your answer to 4 decimals.<BR>\n" );
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document.write( "c)	Using the formula for the sum of the first n terms of a geometric series, what is the sum of the first 12 terms? Please round your answer to 4 decimals.<BR>\n" );
document.write( "Answer:	<BR>\n" );
document.write( "Show work in this space. 	\r<BR>\n" );
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document.write( "d)	What observation can make about these sums? In particular, what number does it appear that the sum will always be smaller than?<BR>\n" );
document.write( "Answer:	\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20901 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20901\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Formula for Sum of n terms <BR>\n" );
document.write( "S(n)=a[1-r^n]/(1-r)<BR>\n" );
document.write( "S(4)=1[1-(1/2)^4]/(1-(1/2)] = 1.8750...<BR>\n" );
document.write( "S(12)= 1[1-(1/2)^12]/[1-(1/2)]=1.9999...<BR>\n" );
document.write( "Getting close and closer to \"2\".<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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