document.write( "Question 34576: Please help me on this problem
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document.write( "solve for x
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document.write( "4/x+3 -1/x^2-5x-24=3/x-8
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document.write( "this is what i have so far:
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document.write( "(x+3)(x-8)4/x+3 -1(x+3)(x-8)/(x+3)(x-8)=3(x+3)(x-8)/x-8
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document.write( "i know that the like terms cancel but i dont know what should be the denominator \n" );
document.write( "
Algebra.Com's Answer #20899 by benni1013(206)![]() ![]() ![]() You can put this solution on YOUR website! I got all the way simplified to 4x-31/(x+3)(x-8)=3/x-8.\r \n" ); document.write( "\n" ); document.write( "4/x+3-1/x^2-5x-24=3/x-8 \n" ); document.write( "Factor. \n" ); document.write( "4/x+3-1/(x-8)(x+3)=3/x-8 \n" ); document.write( "Multiply the missing. \n" ); document.write( "4(x-8)/(x-8)(x+3)-1/(x-8)(x+3)=3/x-8 \n" ); document.write( "Combine \n" ); document.write( "4x-32-1/(x-8)(x+3)=3/x-8 \n" ); document.write( "Simplify \n" ); document.write( "4x-31/(x-8)(x+3)=3/x-8 \n" ); document.write( "Multiply each side by x-8 \n" ); document.write( "4x-31/x+3=3 \n" ); document.write( "Multiply each side by x+3 \n" ); document.write( "4x-31=3x+9 \n" ); document.write( "Subtract 3x \n" ); document.write( "x-31=9 \n" ); document.write( "Add 31 \n" ); document.write( "x=40\r \n" ); document.write( "\n" ); document.write( "LCD is (x-8)(x+3) \n" ); document.write( " |