document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=288306>Question 288306</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two squares have sides of lengths x cm and( 2x + l) cm. The sum of the perimeters of the two squares equals 88 cm. The length of each side of the larger square is\r<BR>\n" );
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document.write( "(a) 7 (b) 15 (c) 29 (d) 57 (e) none of these </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #208962 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=208962\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two squares have sides of lengths x cm and( 2x + l) cm. The sum of the perimeters of the two squares equals 88 cm. The length of each side of the larger square is<BR>\n" );
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document.write( "1st perimeter = 4x cm<BR>\n" );
document.write( "2nd perimeter = 4(2x+1) = 8x+4 cm<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "4x + 8x+4 = 88<BR>\n" );
document.write( "12x = 84<BR>\n" );
document.write( "x = 7<BR>\n" );
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document.write( "1st side: x = 7<BR>\n" );
document.write( "2nd side: 2x+1 = 15<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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document.write( "(a) 7 (b) 15 (c) 29 (d) 57 (e) none of these<BR>\n" );
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