document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=288287>Question 288287</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A dog and a rabbit are 180 meters apart The dog chases the rabbit. For every 9 meters that the dog runs, the rabbit jumps 5 meters. The distance, in meters, that the dog must run in order to overtake the rabbit is\r<BR>\n" );
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document.write( "(a) 184 (b) 189 (c) 225 (d) 405 (e) 1620 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #208950 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=208950\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let them meet after x+180\r<BR>\n" );
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document.write( "The time taken by dog to travel 180+x = time taken by rabbit to go x meters\r<BR>\n" );
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document.write( "time = distance / speed\r<BR>\n" );
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document.write( "x+180 / 9= x/5\r<BR>\n" );
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document.write( "4x+900=9x\r<BR>\n" );
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document.write( "9x-5x=900\r<BR>\n" );
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document.write( "x=900 /4\r<BR>\n" );
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document.write( "225\r<BR>\n" );
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document.write( "225+180= 405 meters </SPAN>\n" );
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