document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=288278>Question 288278</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 2 inches less than 3 times the number of inches in its width. If the perimeter of the rectangle is 28 inches, what is the width and length of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #208946 by </B><A HREF=/tutors/aboutme.mpl?userid=amnd><B>amnd(23)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amnd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amnd><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=208946\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Consider L as its length, and W as its width.\r<BR>\n" );
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document.write( "L is 2 inches less than 3 times W. This means that 3W subtracted by 2 would yield L:<BR>\n" );
document.write( "L = 3W - 2<BR>\n" );
document.write( "3W - L = 2 ... (1)\r<BR>\n" );
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document.write( "The perimeter of a rectangle is twice its width summed with twice its length:<BR>\n" );
document.write( "2w + 2L = 28<BR>\n" );
document.write( "simplified, by dividing with 2:<BR>\n" );
document.write( "W + L = 14 ... (2)\r<BR>\n" );
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document.write( "Add up Equations (1) and (2) (in which L will be eliminated, as -L + L = 0):<BR>\n" );
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document.write( "3W - L = 2<BR>\n" );
document.write( "1W + L = 14<BR>\n" );
document.write( "-------------- +<BR>\n" );
document.write( "4W = 16<BR>\n" );
document.write( "<b>W = 4</b><BR>\n" );
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document.write( "Because W + L = 14, L = 14 - w = 14 - 4 -> <b>L = 10</b> </SPAN>\n" );
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