document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=288227>Question 288227</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is twice the sum of its length and its width. the perimeter is 40 meters and its length is 2 meters more than twice its width. what is the length? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #208907 by </B><A HREF=/tutors/aboutme.mpl?userid=Deina><B>Deina(147)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Deina><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Deina><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=208907\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P = 40<BR>\n" );
document.write( "P = 2(L + W)<BR>\n" );
document.write( "L = 2W + 2<BR>\n" );
document.write( "P = 2(2W + 2 + W)<BR>\n" );
document.write( "P = 2(3W + 2)<BR>\n" );
document.write( "P = 6W + 4 <BR>\n" );
document.write( "40 = 6W + 4 | subtract 4 from each side:<BR>\n" );
document.write( "36 = 6W     | divide each side by 6 <BR>\n" );
document.write( "W = 6 <br><BR>\n" );
document.write( "L = 2*6 + 2 = 14<BR>\n" );
document.write( "2(14 + 6) = 40 and bob's your uncle! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );