document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=288214>Question 288214</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this please:\r<BR>\n" );
document.write( "\n" );
document.write( "Tracy wants to purchase custom-made bumper stickers to advertise her business.  Two websites offer different deals:\r<BR>\n" );
document.write( "\n" );
document.write( "Website A: Pay a fee of $127.00, plus $0.45 per bumper sticker<BR>\n" );
document.write( "Website B: Pay a fee of $100.00, plus $0.60 per bumper sticker.\r<BR>\n" );
document.write( "\n" );
document.write( "At least how many bumper stickers must Tracy purchase in order for Website A to be the better choice?  \r<BR>\n" );
document.write( "\n" );
document.write( "Write an appropriate inequality and solve it algebraically. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #208904 by </B><A HREF=/tutors/aboutme.mpl?userid=Deina><B>Deina(147)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Deina><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Deina><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=208904\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <b>Website A:</b> $127 set up fee plus $0.45/sticker(S) <BR>\n" );
document.write( "C = 127 + 0.45(S)<br><BR>\n" );
document.write( "<b>Website B:</b> $100 set up fee plus $0.60/sticker(S) <BR>\n" );
document.write( "C = 100 + 0.60(S)<br><BR>\n" );
document.write( "To locate the crossover point, where A is less than B, we need to calculate where:<BR>\n" );
document.write( "Website A < Website B, so: <br><BR>\n" );
document.write( "127 + 0.45(S) = 100 + 0.60(S) Now subtract 100 from each side, giving:<BR>\n" );
document.write( "27 + 0.45(S) = 0.60(S)<br> subtract 0.45(S) from each side:<BR>\n" );
document.write( "27 = 0.15(S) Divide each side by 0.15, giving:<BR>\n" );
document.write( "180 = S <br>\r<BR>\n" );
document.write( "\n" );
document.write( "Now replace (S) with <i>any</i> number from 1 to 179 in each of:<BR>\n" );
document.write( "127 + 0.45(S) = Total and <BR>\n" );
document.write( "100 + 0.60(S) = Total to verify that B is indeed lower than A, <BR>\n" );
document.write( "then, while you have calculator in hand, replace (S) with any number greater than 180 and bob's your uncle!<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );