document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=288228>Question 288228</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What formula would I use to solve this problem?\r<BR>\n" );
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document.write( "A radiator contains 6 liters of a 25% anti-freeze solution. How much should be drained and replaced with pure anti-freeze to produce a 33% solution?\r<BR>\n" );
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document.write( "I've been working on a similar problem that I know the answer to in order to figure out how to solve this problem, but I can't seem to find the correct formula for either one. <BR>\n" );
document.write( "My most recent attempt was:<BR>\n" );
document.write( "6(.25 -x) + 1x = 6(.33)<BR>\n" );
document.write( "6.25-6x+x=1.98<BR>\n" );
document.write( "4.23-5x=0<BR>\n" );
document.write( "4.23=5x<BR>\n" );
document.write( "x=.846<BR>\n" );
document.write( "This didn't work for the other problem, so I know this can't be correct here, either. <BR>\n" );
document.write( "Could someone explain the correct formula to me?<BR>\n" );
document.write( "My book doesn't cover percent mixture problems very in depth, just touches on one type and then moves on. Thanks for any help given!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #208900 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=208900\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A radiator contains 6 liters of a 25% anti-freeze solution.<BR>\n" );
document.write( " How much should be drained and replaced with pure anti-freeze to produce a 33% solution?<BR>\n" );
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document.write( "You almost got it:<BR>\n" );
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document.write( "Let x = amt of 25% to be drained, and <BR>\n" );
document.write( "x = amt of pure antifreeze to be added <BR>\n" );
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document.write( ".25(6-x) + x = .33(6)<BR>\n" );
document.write( "1.5 - .25x + x = 1.98<BR>\n" );
document.write( "-.25x + x = 1.98 - 1.5<BR>\n" );
document.write( ".75x = .48<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=.48%2F.75 ALIGN=MIDDLE  ALT=\".48%2F.75\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = .64 liters of 25% removed and .64 liters of pure antifreeze to be added  </SPAN>\n" );
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