document.write( "Question 288217: Please help me with this please:\r
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document.write( "Tracy wants to purchase custom-made bumper stickers to advertise her business. Two websites offer different deals:\r
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document.write( "Website A: Pay a fee of $127.00, plus $0.45 per bumper sticker
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document.write( "Website B: Pay a fee of $100.00, plus $0.60 per bumper sticker.\r
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document.write( "At least how many bumper stickers must Tracy purchase in order for Website A to be the better choice? \r
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document.write( "Write an appropriate inequality and solve it algebraically. \n" );
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Algebra.Com's Answer #208897 by jaydducote(11)![]() ![]() You can put this solution on YOUR website! You want website A to be the better choice. In this case, since you are asked about the price of two different companies, the lower price is preferred. An equal price is not a better price, so you will need to use > or < instead of greater/less than OR equal to. Since you want website A to be a smaller price, your inequality needs to show that Website A < Website B.\r \n" ); document.write( "\n" ); document.write( "Turn each website into an algebraic expression by identifying the variable and the constant. The variable here is the bumper sticker. The word \"per\" is always an indicator for a variable. So your expressions could look like this: \n" ); document.write( "Website A: 127+0.45x \n" ); document.write( "Website B: 100+0.60x\r \n" ); document.write( "\n" ); document.write( "The price of either company will be the fee plus a unit price times the number of units.\r \n" ); document.write( "\n" ); document.write( "Now plug those expressions into the inequality: \n" ); document.write( "Website A < Website B \n" ); document.write( "127+0.45x<100+0.60x\r \n" ); document.write( "\n" ); document.write( "Combine like terms. Since 127 is bigger and on the left, I would subtract 100 from both sides to cancel it out on the right. \n" ); document.write( "127-100+0.45x<100-100+0.60x \n" ); document.write( "27+0.45x<0.60x \n" ); document.write( "Now do the same with the 0.45x \n" ); document.write( "27+0.45x-0.45x<0.60x-0.45x \n" ); document.write( "27<0.15x \n" ); document.write( "Now since the 0.15 is a coefficient of x, you need to divide. \n" ); document.write( "27/0.15<0.15x/0.15 \n" ); document.write( "180 |