document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=288175>Question 288175</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Need help adding and subtracting (a-1)/(a+1)+(a+1)/(a-1) do they cancel each other out? and (b)/(b-1)+(2b)/(b^2-1)?????  Thank you in advance! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #208858 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=208858\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> NO they do not cancel.<BR>\n" );
document.write( "(a-1)/(a+1)+(a+1)/(a-1) Find a common denominator & add.<BR>\n" );
document.write( "[(a-1)(a-1)+(a+1)(a+1)]/(a+1)(a-1)<BR>\n" );
document.write( "[a^2-2a+1+a^2+2a+1]/(a^2-1)<BR>\n" );
document.write( "[2a^2+2]/(a^2-1)<BR>\n" );
document.write( "2(a^2+1)/(a^2-1) ans.<BR>\n" );
document.write( "---------------------------<BR>\n" );
document.write( "(b)/(b-1)+(2b)/(b^2-1) <BR>\n" );
document.write( "[b(b^2-1)+2b(b-1)]/(b-1)(b^2-1)<BR>\n" );
document.write( "b^3-b+2b^3-2b]/(b-1)(b^2-1)<BR>\n" );
document.write( "(3b^3-3b)/(b-1)(b^2-1)<BR>\n" );
document.write( "3b(b^2-1)/(b-1)(b^2-1) cancel out the (b^2-1) terms.<BR>\n" );
document.write( "3b/(b-1) ans. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );