document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=288138>Question 288138</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have worked this problem several times and come up mwith different answers i think i am missing some steps please if someone can work the problem so I can see how you come up with your answers.\r<BR>\n" );
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document.write( "Two airplanes are leaving O'Hare at the same time, one bound for New York and the other for California. The one heading to California has a tail wind and is thus going 25 MPH faster than the one headed for New York. If after one hour they are 575 miles apart, what are their speeds?\r<BR>\n" );
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document.write( "Eric </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #208839 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=208839\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assuming one is going due West & the other is going due East then their distances are additive.<BR>\n" );
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document.write( "575=(x+25)*1+x*1<BR>\n" );
document.write( "575=x+25+x<BR>\n" );
document.write( "2x=575-25<BR>\n" );
document.write( "2x=550<BR>\n" );
document.write( "x=550/2<BR>\n" );
document.write( "x=275 mph for the plane headed for New York.<BR>\n" );
document.write( "175+25=300 mph for the plane headed for California.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "275+300=575<BR>\n" );
document.write( "575=575<BR>\n" );
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