document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=288136>Question 288136</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am taking a college course and this is a homework problem I cant solve or for that matter understand\r<BR>\n" );
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document.write( "Find the equation for the line passing through the origin and perpendicular to y = ½ x – 2\r<BR>\n" );
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document.write( "Eric </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #208821 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=208821\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First recall that perpendicular lines have slopes that are the negative reciprocal of each other.<BR>\n" );
document.write( "In other words, if one of the lines has a slope<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m+=+1%2F3 ALIGN=MIDDLE  ALT=\"m+=+1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >, then the slope of the perpendicular line is<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m+=+-3 ALIGN=MIDDLE  ALT=\"m+=+-3\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "In your problem, you are given the line<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+%281%2F2%29x-2 ALIGN=MIDDLE  ALT=\"y+=+%281%2F2%29x-2\"   DISABLED_style= \"max-width:90%; height:auto;\" > whose slope<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m+=+1%2F2 ALIGN=MIDDLE  ALT=\"m+=+1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >. The new perpendicular line will then have a slope<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m+=+-2 ALIGN=MIDDLE  ALT=\"m+=+-2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, so using the slope-intercept form of the linear equation, we have:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+-2x%2Bb ALIGN=MIDDLE  ALT=\"y+=+-2x%2Bb\"   DISABLED_style= \"max-width:90%; height:auto;\" > To find the value of b (the y-intercept), substitute the x- and y-coordinates of the origin (0, 0).<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+-2x%2Bb ALIGN=MIDDLE  ALT=\"y+=+-2x%2Bb\"   DISABLED_style= \"max-width:90%; height:auto;\" > Substitute x = 0 and y = 0.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0+=+-2%280%29%2Bb ALIGN=MIDDLE  ALT=\"0+=+-2%280%29%2Bb\"   DISABLED_style= \"max-width:90%; height:auto;\" > so b = 0.<BR>\n" );
document.write( "The final equation will be:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28y+=+-2x%29 ALIGN=MIDDLE  ALT=\"highlight%28y+=+-2x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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