document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=288114>Question 288114</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do I simplify e^-lne?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #208812 by </B><A HREF=/tutors/aboutme.mpl?userid=amnd><B>amnd(23)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amnd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amnd><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=208812\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It is fairly simple. You only need to recall the relation between the exponential number (e) and natural logarithm (ln). ln(x) is simply the inverse of the function e^x, which means that:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=e%5E%28lnx%29=x ALIGN=MIDDLE  ALT=\"e%5E%28lnx%29=x\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "As with ordinary logarithm, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=N%2Aln%28x%29=ln%28x%5EN%29 ALIGN=MIDDLE  ALT=\"N%2Aln%28x%29=ln%28x%5EN%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. For this situation, x = e and N = -1, yielding:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=e%5E%28-ln%28e%29%29=e%5E%28ln%28e%5E%28-1%29%29%29=e%5E%28-1%29=1%2Fe ALIGN=MIDDLE  ALT=\"e%5E%28-ln%28e%29%29=e%5E%28ln%28e%5E%28-1%29%29%29=e%5E%28-1%29=1%2Fe\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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