document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=288130>Question 288130</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Which of the following division problems is impossible?\r<BR>\n" );
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document.write( "A. 15/1<BR>\n" );
document.write( "B. 15/0<BR>\n" );
document.write( "C. 0/15<BR>\n" );
document.write( "D. 15/45 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #208806 by </B><A HREF=/tutors/aboutme.mpl?userid=amnd><B>amnd(23)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amnd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amnd><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=208806\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A. 15/1 = 15, so this is valid<BR>\n" );
document.write( "C. 0/15 = 0 , 0/15 is the same as 0 x 1/15, and zero multiplied by anything stays as zero<BR>\n" );
document.write( "D. 15/45 = 1/3, also valid, as both of the numbers are rational\r<BR>\n" );
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document.write( "The only one impossible to do would be <b>B. 15/0</b>, as anything divided by zero is undefined.\r<BR>\n" );
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document.write( "Look at division as the inverse of multiplication. Say that A/B = C, this would mean B x C = A. Let's pretend A is 15 and B is zero, while C is a constant.\r<BR>\n" );
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document.write( "15/0 = C would mean that C x 0 = 15. Zero multiplied by anything is meant to stay as zero, so it would be impossible to find a number to multiply it with that would lead to 15. </SPAN>\n" );
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