document.write( "Question 4560: Solve problem to 3 significant digits\r
\n" ); document.write( "\n" ); document.write( "2^x = 0.0525
\n" ); document.write( "

Algebra.Com's Answer #2088 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
\"2%5Ex+=+0.0525\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Take the ln of each side of the equation:
\n" ); document.write( "\"ln%282%5Ex%29+=+ln+0.0525\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "By the third law of logarithms, the exponent x becomes the coefficient of the ln2:
\n" ); document.write( "\"x+ln+2+=+ln+0.0525\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Divide both sides of the equation by ln 2:
\n" ); document.write( "\"x+=+%28ln+0.0525%29%2F%28ln+2%29\"
\n" ); document.write( "\"+x+=+-4.25\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "R^2 at SCC
\n" ); document.write( "
\n" );