document.write( "Question 288049: If a small circle's diameter is a large circle's radius, then the small
\n" ); document.write( "circle is ____% of the large circle's area?\r
\n" ); document.write( "\n" ); document.write( "a) 20 b) 25 c) 30 d) 40 e) 50
\n" ); document.write( "

Algebra.Com's Answer #208759 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "The green line is the small circle's diameter and also the \r\n" );
document.write( "large circle's radius.  Suppose the green line is 2 inches long.\r\n" );
document.write( "Then the small circle's radius is 1, the red line:\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Area of small circle = \"pi%2Aradius%5E2=pi%2A1%5E2=pi%2A1=pi\"\r\n" );
document.write( "\r\n" );
document.write( "Area of large circle = \"pi%2Aradius%5E2=pi%2A2%5E2=pi%2A4=4pi\"\r\n" );
document.write( "\r\n" );
document.write( "Since the big circle's area is 4 times the small circle's area,\r\n" );
document.write( "the small circle's area is \"1%2F4\" of the big circle's area\r\n" );
document.write( "and \"1%2F4\" is the same as 25%. So the correct choice is b)\r\n" );
document.write( "\r\n" );
document.write( "Edwin

\n" ); document.write( "
\n" ); document.write( "
\n" );