document.write( "Question 288025: PlEASE help with polynomial long division.I've tried a million times and just cant get it. :/ (x^3+2x^2+3x-6)/(x-1) and (n^3-27)/(n-3) PlEASE show steps also =) Thanks in advance. \n" ); document.write( "
Algebra.Com's Answer #208753 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
Polynomial division is not much different than regular long division.\r
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\n" ); document.write( "\n" ); document.write( "Your dividend is the expression you want to divide into.\r
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\n" ); document.write( "\n" ); document.write( "It is \"x%5E3+%2B+2x%5E2+%2B+3x+-+6\"\r
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\n" ); document.write( "\n" ); document.write( "Your divisor is the expression you want to divide into the dividend.\r
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\n" ); document.write( "\n" ); document.write( "It is \"x-1\"\r
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\n" ); document.write( "\n" ); document.write( "You set up your equation as shown in step 1 of the following picture.\r
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\n" ); document.write( "\n" ); document.write( "In step 1 you are dividing \"x%5E3\" by \"x\" to get \"x%5E3+-+x%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "You subtract that from \"x%5E3+%2B+2x%5E2\" to get a remainder of \"3x%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "You bring down the \"3x\" from the original dividend as shown in step 1 to make the remainder equal to \"3x%5E2+%2B+3x\" as shown in step 2.\r
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\n" ); document.write( "\n" ); document.write( "You divide \"3x%5E2\" of that remainder by \"x\" to get \"3x\" which you place above the original dividend as shown in step 1.\r
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\n" ); document.write( "\n" ); document.write( "You multiply \"x-1\" times \"3x\" to get \"3x%5E2+-+3x\" which you subtract from \"3x%5E2+%2B+3x\" as shown in step 2.\r
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\n" ); document.write( "\n" ); document.write( "You get a remainder of \"6x\".\r
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\n" ); document.write( "\n" ); document.write( "You bring down the \"-6\" from the original dividend as shown in step 1 to get a remainder of \"6x-6\" as shown in step 3.\r
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\n" ); document.write( "\n" ); document.write( "You divide \"x\" into \"6x\" as shown in step 2 to get \"6\" which you place above \"3x\" of the original dividend as shown in step 1.\r
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\n" ); document.write( "\n" ); document.write( "You multiply \"x-1\" times 6 to get \"6x-6\" which you subtract from \"6x-6\" to get a remainder of 0 as shown in step 4.\r
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\n" ); document.write( "\n" ); document.write( "You stop at step 4 because you have nothing left to divide into.\r
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\n" ); document.write( "\n" ); document.write( "Your answer is \"x%5E2+%2B+3x+%2B+6\" with zero remainder.\r
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\n" ); document.write( "\n" ); document.write( "To confirm that it's good, you multiply it by \"x-1\" to get the original dividend.\r
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\n" ); document.write( "\n" ); document.write( "That happens in steps 5 and 6 with the result shown in step 7.\r
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\n" ); document.write( "\n" ); document.write( "Since you are able to get the same dividend that you started with, your division is good.\r
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\n" ); document.write( "\n" ); document.write( "The result of your division is \"x%5E2+%2B+3x+%2B+6\" as shown in step 1.\r
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\n" ); document.write( "\n" ); document.write( "Your original dividend is \"x%5E3+%2B+2x%5E2+%2B+3x+-+6\" as shown in step and confirmed in step 7.\r
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\n" ); document.write( "\n" ); document.write( "You are always dividing the highest order of the divider into the highest order of the remainder of the dividend.\r
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\n" ); document.write( "\n" ); document.write( "You are then always multiplying the whole divisor by the result of that division.\r
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\n" ); document.write( "\n" ); document.write( "You are then subtracting the result of that multiplication from the remainder.\r
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\n" ); document.write( "\n" ); document.write( "Once you get your remainder from the division, you are always bringing down the next lower order term from the original dividend.\r
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\n" ); document.write( "\n" ); document.write( "Follow the steps through and you'll see how it was done.\r
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\n" ); document.write( "\n" ); document.write( "Now we'll go on to your next problem.\r
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\n" ); document.write( "\n" ); document.write( "That problem worked out by hand is shown below:\r
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\n" ); document.write( "\n" ); document.write( "With this problem, you are dividing \"n%5E3+-+27\" by \"n-1\".\r
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\n" ); document.write( "\n" ); document.write( "Since you are missing lower order exponents in the dividend, you need to fill them in. \r
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\n" ); document.write( "\n" ); document.write( "That will make further processing easier.\r
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\n" ); document.write( "\n" ); document.write( "\"n%5E3+-+27\" is equal to \"n%5E3+%2B+0n%5E2+%2B+0n+-+27\" after you fill in the missing lower order exponent terms.\r
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\n" ); document.write( "\n" ); document.write( "Now you are ready to begin.\r
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\n" ); document.write( "\n" ); document.write( "You are always dividing the highest order of the divisor into the highest order of the remainder of the dividend.\r
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\n" ); document.write( "\n" ); document.write( "When you start the division, the remainder of the dividend is the dividend itself.\r
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\n" ); document.write( "\n" ); document.write( "You Divide \"n\" into \"n%5E3\" as shown in step 1.\r
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\n" ); document.write( "\n" ); document.write( "You get \"n%5E2\" which you place above the \"n%5E3\" as shown in step 1.\r
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\n" ); document.write( "\n" ); document.write( "You multiply \"n-3\" times \"n%5E2\" to get \"n%5E3+-+3n%5E2\" which you subtract from \"n%5E3+%2B+0n%5E2\" as shown in step 1.\r
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\n" ); document.write( "\n" ); document.write( "You get a remainder of \"3n%5E2\" and bring down \"0n\" from the original dividend to get a remainder of \"3n%5E2+%2B+0n\" as shown in step 2.\r
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\n" ); document.write( "\n" ); document.write( "You divide \"3n%5E2\" by \"n\" to get \"3n\" which you place above \"0n%5E2\" as shown in step 1.\r
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\n" ); document.write( "\n" ); document.write( "You multiply \"n-3\" times \"3n\" to get \"3n%5E2+-+9n\" which you subtract from \"3n%5E2+%2B+0n\" as shown in step 2.\r
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\n" ); document.write( "\n" ); document.write( "You get a remainder of \"9n\".\r
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\n" ); document.write( "\n" ); document.write( "You bring down the \"-27\" from the original dividend as shown in step 1.\r
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\n" ); document.write( "\n" ); document.write( "You get a remainder of \"9n-27\" as shown in step 3.\r
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\n" ); document.write( "\n" ); document.write( "You divide \"9n\" by \"n\" to get 9.\r
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\n" ); document.write( "\n" ); document.write( "You place that above the \"0n\" as shown in step 1.\r
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\n" ); document.write( "\n" ); document.write( "You multiply \"n-3\" by \"9\" to get \"9n+-+27\".\r
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\n" ); document.write( "\n" ); document.write( "You subtract \"9n-27\" from \"9n-27\" as shown in step 3 to get a remainder of 0 as shown in step 4.\r
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\n" ); document.write( "\n" ); document.write( "Since there is nothing left to divide, you are done.\r
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\n" ); document.write( "\n" ); document.write( "You then confirm the answer is correct by multiplying \"n%5E2+%2B+3n+%2B+9\" as shown in step 1 by \"n-3\" to see if you can get back to the original dividend.\r
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\n" ); document.write( "\n" ); document.write( "That's done in steps 5 and 6 with the result shown in step 7.\r
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\n" ); document.write( "\n" ); document.write( "Since you get the original dividend, the division is good.\r
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\n" ); document.write( "\n" ); document.write( "The result of the division is \"n%5E2+%2B+3n+%2B+9\" as shown in step 1.\r
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\n" ); document.write( "\n" ); document.write( "The original dividend is \"n%5E3+-+27\" as shown above step 1 and confirmed in step 7.\r
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