document.write( "Question 287328: This is a two-part problem.\r
\n" ); document.write( "\n" ); document.write( "For \"+f%28x%29+=+sqrt+%28+1-2x+%29+\" \"+g%28x%29+=+-x%2B3+\"\r
\n" ); document.write( "\n" ); document.write( "A) Find (FºG)(x)\r
\n" ); document.write( "\n" ); document.write( "B) Find the domain of (FºG)(x)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "What I have so far, which I am not totally sure about it:
\n" ); document.write( "(FºG)(x) = \"+sqrt+%28+1-2%28-x%2B3%29+%29+\" simplified into \"+sqrt+%28+2x-5+%29+\"\r
\n" ); document.write( "\n" ); document.write( "Is that correct for step A)? And how do I find the domain for step B)?
\n" ); document.write( "

Algebra.Com's Answer #208736 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
You did part A exactly right!

\n" ); document.write( "For the domain, you just have to find the set of acceptable values for x. The function you found in part A has the x inside a square root. Since we must have a non-negative (zero or positive) number inside the square root, the only values we can allow x to be are those those that make 2x-5 non-negative. In other \"words\"
\n" ); document.write( "\"2x+-+5+%3E=+0\"
\n" ); document.write( "Solving this:
\n" ); document.write( "\"2x+%3E=+5\"
\n" ); document.write( "\"x+%3E=+5%2F2\"
\n" ); document.write( "This describes the acceptable values of x. This is the domain.
\n" ); document.write( "
\n" );