document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=288001>Question 288001</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that the width of a rectangle is 5 inches shorter than the length and that the perimeter of the rectangle is 50 inches. Set up an equation for the perimeter involving only L, the length in the rectangle.\r<BR>\n" );
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document.write( "Also solve this equation algebraically to find the length of the rectangle. Find the width as well. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #208705 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=208705\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W=L-5  <BR>\n" );
document.write( "P=2L+2W<BR>\n" );
document.write( "50=2L+2(L-5)<BR>\n" );
document.write( "50=2L+2L-10<BR>\n" );
document.write( "4L=50+10<BR>\n" );
document.write( "4L=60<BR>\n" );
document.write( "L=60/4<BR>\n" );
document.write( "L=15 ANS.<BR>\n" );
document.write( "W=15-5=10 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "50=2*15+2+10<BR>\n" );
document.write( "50=30+20<BR>\n" );
document.write( "50=50<BR>\n" );
document.write( "    </SPAN>\n" );
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