document.write( "Question 287848: one factor of x^3 + 2x^3 - 11x - 12 is x + 4. Find the remaining factors. \n" ); document.write( "
Algebra.Com's Answer #208654 by Edwin McCravy(20056)\"\" \"About 
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one factor of \"x%5E3+%2B+2x%5E3+-+11x+-+12\" is \"x+%2B+4\".
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document.write( "Since x + 4 is a factor, then x = -4 is a zero.  Use synthetic\r\n" );
document.write( "division with -4\r\n" );
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document.write( " -4 |  1  2 -11 -12\r\n" );
document.write( "    |    -4   8  12\r\n" );
document.write( "       1 -2  -3   0\r\n" );
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document.write( "So we have factored the polynomial as\r\n" );
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document.write( "\"%28x%2B4%29%28x%5E2-2x-3%29\"\r\n" );
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document.write( "Now we factor the trinomial:\r\n" );
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document.write( "\"%28x%2B4%29%28x-3%29%28x%2B1%29\"  \r\n" );
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document.write( "Edwin
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