document.write( "Question 287930: You have 2 drums of milk, one contains 16% butterfat, the other contains 48% butterfat. You need 40 gallons of milk at 30% butterfat. How many gallons of each do you have to mix?
\n" ); document.write( "Thank you for your time.
\n" ); document.write( "Regards,
\n" ); document.write( "Beth \n" ); document.write( "
Algebra.Com's Answer #208650 by ankor@dixie-net.com(22740)\"\" \"About 
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You have 2 drums of milk, one contains 16% butterfat, the other contains 48% butterfat.
\n" ); document.write( " You need 40 gallons of milk at 30% butterfat.
\n" ); document.write( " How many gallons of each do you have to mix?
\n" ); document.write( ":
\n" ); document.write( "Let x = amt of 48% milk
\n" ); document.write( "the result is to be 40 gal, therefore:
\n" ); document.write( "(40-x) = amt of 16% milk
\n" ); document.write( ":
\n" ); document.write( "At typical mixture equation using decimal equiv of percent:
\n" ); document.write( ".48x + .16(40-x) = .30(40)
\n" ); document.write( ":
\n" ); document.write( ".48x + 6.4 - .16x = 12
\n" ); document.write( ":
\n" ); document.write( ".48x - .16x = 12 - 6.4
\n" ); document.write( ":
\n" ); document.write( ".32x = 5.6
\n" ); document.write( "x = \"5.6%2F.32\"
\n" ); document.write( "x = 17.5 gal of 48% milk
\n" ); document.write( "and
\n" ); document.write( "40 - 17.5 = 22.5 gal of 16% milk
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "Check solution in original equation
\n" ); document.write( ".48(17.5) + .16(22.5) = .30(40)
\n" ); document.write( "8.4 + 3.6 = 12; confirms our solutions \n" ); document.write( "
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