document.write( "Question 287904: pat rode 30 miles. bob covered twice distance adding one hour and going five miles faster per hour. what was speed of each \n" ); document.write( "
Algebra.Com's Answer #208646 by ankor@dixie-net.com(22740)\"\" \"About 
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pat rode 30 miles. bob covered twice distance adding one hour and going five
\n" ); document.write( " miles faster per hour. what was speed of each
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\n" ); document.write( "Let s = Pat's speed
\n" ); document.write( "then
\n" ); document.write( "(s+5) = Bob's speed
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\n" ); document.write( "Write a time equation: Time = Distance/speed
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\n" ); document.write( "Pat's time + 1 hr = Bob's time
\n" ); document.write( "\"30%2Fs\" + 1 = \"60%2F%28%28s%2B5%29%29\"
\n" ); document.write( "multiply by s(s+5), results:
\n" ); document.write( "30(s+5) + s(s+5) = 60s
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\n" ); document.write( "30s + 150 + s^2 + 5s = 60s
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\n" ); document.write( "s^2 + 30s + 5s - 60s + 150 = 0
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\n" ); document.write( "s^2 - 25s + 150 = 0
\n" ); document.write( "Factor
\n" ); document.write( "(s - 10)(s - 15) = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "s = 10 mph is Pat's speed; then Bob = 15 mph
\n" ); document.write( "and
\n" ); document.write( "s = 15 mph is Pat's speed; then Bob = 20 mph
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\n" ); document.write( "Check both solutions by finding the times for each (should be a 1hr difference)
\n" ); document.write( "Bob: 60/15 = 4 hr
\n" ); document.write( "Pat: 30/10 = 3 hr
\n" ); document.write( "and
\n" ); document.write( "Bob: 60/20 = 3 hr
\n" ); document.write( "Pat: 30/15 = 2 hr
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