document.write( "Question 34577: please help me with this problem
\n" ); document.write( "solve for x\r
\n" ); document.write( "\n" ); document.write( "x=3/x+1\r
\n" ); document.write( "\n" ); document.write( "this is what i have so far
\n" ); document.write( "x(x+1)=3
\n" ); document.write( "(x+3)(x-1)=0
\n" ); document.write( "?
\n" ); document.write( "

Algebra.Com's Answer #20863 by MrTillman(3)\"\" \"About 
You can put this solution on YOUR website!
First thing you need to do is get rid of the fraction, thus you multiply x by each term, which gives you a quadratic equation: \"x%28x%29=%28x%293%2Fx+%2B+1%28x%29\"
\n" ); document.write( " \"x%5E2=3x%2Fx+%2B+x\"
\n" ); document.write( " \"x%5E2=3+%2B+x\" set equal to 0
\n" ); document.write( " \"x%5E2-x-3=0\"
\n" ); document.write( "This quadractic doesnt factor, so you have to 'complete the square' like this: first isolate the variable terms to get \"x%5E2-x=3\"
\n" ); document.write( " Make sure first term has coefficient of 1, it does
\n" ); document.write( " Then take coefficient of middle term (-x) and find the perfect square trinomial like this: \"%28-1%2F2%29%5E2\" which gives you 1/4 or .25
\n" ); document.write( " Just add this to both sides to \"x%5E2-x%2B1%2F4=3%2B1%2F4\" and you get \"x%5E2-x%2B1%2F4=13%2F4\"
\n" ); document.write( "Now you can factor the left side of this to get \"%28x-1%2F2%29%5E2=13%2F4\"
\n" ); document.write( "Now you can solve for x using the square root method by taking square root of both sides to get \"x-1%2F2+=+sqrt%2813%2F4%29\" = \"x-1%2F2=1.803\" \"x+=+1.803%2B1%2F2\" \r
\n" ); document.write( "\n" ); document.write( "x= 2.303 \r
\n" ); document.write( "\n" ); document.write( "Check 2.303 = 3/2.303 + 1
\n" ); document.write( "2.303=1.303+1 yes
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