document.write( "Question 287839: A 1000-seat multiplex is divided into 3 theaters. There are 204 seats in Theater 1, and 108 more seats in Theater 2 than Theater 3. How many seats are in Theater 2?\r
\n" ); document.write( "\n" ); document.write( "a) 796 b) 452 c) 688 d) 344 e) 542
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Algebra.Com's Answer #208618 by Stitch(470)\"\" \"About 
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Set-Up
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\n" ); document.write( "Let A = # of seats in theater 1
\n" ); document.write( "Let B = # of seats in theater 2
\n" ); document.write( "Let C = # of seats in theater 3\r
\n" ); document.write( "\n" ); document.write( "Equation 1: \"A++=+204\"
\n" ); document.write( "Equation 2: \"B+=+108+%2B+C\"
\n" ); document.write( "Equation 3: \"A+%2B+B+%2B+C+=+1000\"\r
\n" ); document.write( "\n" ); document.write( "Solution:
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\n" ); document.write( "We were given that A = 204, And equation 2 is solved for B. You can substitute these values into equation 3.
\n" ); document.write( "Equation 3: \"A+%2B+B+%2B+C+=+1000\"
\n" ); document.write( "\"204+%2B+%28108+%2B+C%29+%2B+C+=+1000\" Simplify
\n" ); document.write( "\"312+%2B+2C+=+1000\" Subtract 312 from both sides
\n" ); document.write( "\"2C+=+688\" Divide both sides by 2
\n" ); document.write( "\"highlight%28C+=+344%29\"\r
\n" ); document.write( "\n" ); document.write( "Now plug 344 into equation 2 for C.
\n" ); document.write( "Equation 2: \"B+=+108+%2B+C\"
\n" ); document.write( "\"B+=+108+%2B+344\"
\n" ); document.write( "\"highlight%28B+=+452%29\"
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