document.write( "Question 34574This question is from textbook Algebra 2
\n" ); document.write( ": 5/(3+i)\r
\n" ); document.write( "\n" ); document.write( "In this case the (i) stands for imaginary number.
\n" ); document.write( "The answer is (3-i)/2.
\n" ); document.write( "I don't know how my teacher came up with the answer.
\n" ); document.write( "Thank you so much! Please respond as soon as possible! \n" ); document.write( "
Algebra.Com's Answer #20861 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
5/(3+i)
\n" ); document.write( "Multiply numerator and denominator by (3-i) as follows:
\n" ); document.write( "[5(3-i)]/[(3+i)(3-i)]
\n" ); document.write( "Notice the denominator is in the form (a+b)(a-b)
\n" ); document.write( "so the denominator takes on the form a^2-b^2, as follows:
\n" ); document.write( "=[5(3-i)]/[3^2 - i^2]
\n" ); document.write( "But i^2=-1, as you probably just learned, so you get:
\n" ); document.write( "=[5(3-i)]/[9+1]
\n" ); document.write( "=[5(3-i)]/10
\n" ); document.write( "=(3-i)/2
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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