document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=287567>Question 287567</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Diagonal brace. The width of a rectangular gate is 2 meters (m) larger than its height. The diagonal brace measures sqrt of 6 meters.<BR>\n" );
document.write( "Length x + 2<BR>\n" );
document.write( "Height x<BR>\n" );
document.write( "Diagonal Brace sqrt of 6. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #208537 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=208537\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> So you have a right triangle with sides x and x+2 and hypotenuse sqrt(6). By the Pythagorean Theorem:\r<BR>\n" );
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document.write( "x^2 + (x+2)^2 = (sqrt(6))^2\r<BR>\n" );
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document.write( "x^2 + x^2 + 4x + 4 = 6\r<BR>\n" );
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document.write( "2x^2 + 4x - 2 = 0\r<BR>\n" );
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document.write( "Divide both sides by 2:\r<BR>\n" );
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document.write( "x^2 + 2x - 1 = 0\r<BR>\n" );
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document.write( "Use the quadratic formula to find x and calculate x+2.\r<BR>\n" );
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