document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=287765>Question 287765</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The period T (time in seconds for one complete cycle) of a simple pendulum is related to the length L (in feet) of the pendulum by the formula 8T^2 =rr^2L. If a child is on a swing with a 10-foot chain, then how long does it take to complete one cycle of the swing?\r<BR>\n" );
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document.write( "This is so confusing, can you explain it to me? I appreciate it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #208529 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=208529\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Your rr should be pi which equals 3.14<BR>\n" );
document.write( "pi is the relationship between the circumference and the radius of a circle. <BR>\n" );
document.write( "So it should read<BR>\n" );
document.write( "8T^2=(3.14)^2*L<BR>\n" );
document.write( "plug in 10 for L<BR>\n" );
document.write( "and solve for T<BR>\n" );
document.write( "8T^2=(3.14)^2*10<BR>\n" );
document.write( "T=3.51063 seconds or almost 4 seconds\r<BR>\n" );
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