document.write( "Question 287764: 2x-5y=7
\n" ); document.write( "8=x-4y\r
\n" ); document.write( "\n" ); document.write( "I have to solve using substitution. My answer is (20,3)which means x=20 and y=3.
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Algebra.Com's Answer #208525 by Alan3354(69443)\"\" \"About 
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2x-5y=7
\n" ); document.write( "8=x-4y --> x = 4y + 8
\n" ); document.write( "Sub for x into 1st eqn:
\n" ); document.write( "2(4y+8) - 5y = 7
\n" ); document.write( "8y+16 - 5y = 7
\n" ); document.write( "3y = -9
\n" ); document.write( "y = -3
\n" ); document.write( "-------
\n" ); document.write( "x = -4
\n" ); document.write( "------
\n" ); document.write( "I have to solve using substitution. My answer is (20,3)which means x=20 and y=3.
\n" ); document.write( "Check (20,3)
\n" ); document.write( "2x-5y=7
\n" ); document.write( "2*20 - 5*3 =? 7
\n" ); document.write( "It doesn't.
\n" ); document.write( "-------------
\n" ); document.write( "It's (-4,-3)
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