document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=287754>Question 287754</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 2 inches more than its width. The area of the rectangle is 15 inches. What are the length and width of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #208516 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=208516\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the width be x\r<BR>\n" );
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document.write( "the length will be x+2\r<BR>\n" );
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document.write( "Area = L*W\r<BR>\n" );
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document.write( "=x(x+2)\r<BR>\n" );
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document.write( "15=x^2+2x\r<BR>\n" );
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document.write( "x^2+2x-15=0\r<BR>\n" );
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document.write( "x^2+5x-3x-15=0\r<BR>\n" );
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document.write( "x(x+5)-3(x+5)=0\r<BR>\n" );
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document.write( "(x+5)(x-3)=0\r<BR>\n" );
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document.write( "x=-5 or 3\r<BR>\n" );
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document.write( "width = 3 and length = 5\r<BR>\n" );
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document.write( " </SPAN>\n" );
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