document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=287756>Question 287756</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value of k such that the graphs of x + 7y = 70 and y + 3 = kx are perpendicular. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #208515 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=208515\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the value of k such that the graphs of x + 7y = 70 and y + 3 = kx are perpendicular.<BR>\n" );
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document.write( "Solve each equation for \"y\":<BR>\n" );
document.write( "y = (-1/7)x + 10<BR>\n" );
document.write( "---<BR>\n" );
document.write( "y = kx - 3<BR>\n" );
document.write( "---<BR>\n" );
document.write( "If the 2nd equation is perpendicular to the 1st,<BR>\n" );
document.write( "(-1/7)k = -1<BR>\n" );
document.write( "(1/7)k = 1\r<BR>\n" );
document.write( "\n" );
document.write( "k = 7<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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