document.write( "Question 4546: How would I right an equation of the line perpendicular to the line
\n" ); document.write( "l: y=-1/4x+2 and passes through point P(3,0)?
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Algebra.Com's Answer #2085 by granville(2)\"\" \"About 
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Two lines are perpendicular if their slopes are negative reciprocals. In your example, the given slope is -1/4. (I know that because it is the coefficient of x.) Since the negative reciprocal of -1/4 is +4/1, or 4, the slope of the new line is 4. So, the new line must look like this\r
\n" ); document.write( "\n" ); document.write( "y = 4x + ___\r
\n" ); document.write( "\n" ); document.write( "I can fill in the blank if I use the point you gave, (3,0). This means that when x = 3, y = 0. Substitute them into my equation above.\r
\n" ); document.write( "\n" ); document.write( "0 = 4(3) + ____
\n" ); document.write( "0 = 12 + ____\r
\n" ); document.write( "\n" ); document.write( "So, the blank must have a -12. Therefore, the line is\r
\n" ); document.write( "\n" ); document.write( "y = 4x - 12.\r
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