document.write( "Question 287727: log(d)+log(2d+1)=log(7d) \n" ); document.write( "
Algebra.Com's Answer #208485 by stanbon(75887)\"\" \"About 
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log(d)+log(2d+1)=log(7d)
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\n" ); document.write( "log(d(2d+1)) = log(7d)
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\n" ); document.write( "2d^2 + d = 7d
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\n" ); document.write( "2d^2-6d = 0
\n" ); document.write( "d(2d-6) = 0
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\n" ); document.write( "d = 0 or d = 3
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\n" ); document.write( "d cannot be 0 because log(7*0) does not exist.
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\n" ); document.write( "Only solution:
\n" ); document.write( "d = 3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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