document.write( "Question 287607: A box is being constructed by cutting 3-inch squares from the corners of a rectangular sheet of metal that is 4 inches longer than it is wide. If the box is to have a volume of 135 cubic inches, find the dimensions of the metal sheet. \n" ); document.write( "
Algebra.Com's Answer #208445 by ankor@dixie-net.com(22740)\"\" \"About 
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A box is being constructed by cutting 3-inch squares from the corners of a
\n" ); document.write( " rectangular sheet of metal that is 4 inches longer than it is wide.
\n" ); document.write( "If the box is to have a volume of 135 cubic inches, find the dimensions of the metal sheet.
\n" ); document.write( ":
\n" ); document.write( "Assume this is an open box
\n" ); document.write( "Height = 3 inches
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\n" ); document.write( "Let x = width of the box
\n" ); document.write( "then
\n" ); document.write( "(x+4) = length of the box
\n" ); document.write( ":
\n" ); document.write( "Volume
\n" ); document.write( "3x(x+4) = 135
\n" ); document.write( "3x^2 + 12x - 135 = 0
\n" ); document.write( "Factor
\n" ); document.write( "(3x + 27)(x - 5) = 0
\n" ); document.write( "positive solution
\n" ); document.write( "x = 5 inches is the width
\n" ); document.write( "then
\n" ); document.write( "5+4 = 9 inches is the length
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\n" ); document.write( "Cutting the 3 inches corners adds 6 inches to each dimension
\n" ); document.write( "Metal sheet = 15 by 11 inches
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