document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=287543>Question 287543</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having trouble with this problem. I can't figure out how to post a diagram so I will try and describe it. If you can tell me how to post it or give me an email to send it I would be happy to do that.\r<BR>\n" );
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document.write( "I have a circle with a diameter drawn in. The radius (indicated on half my diam.) is labeled x. The end of x that is on the circle is also the endpoint of a chord. The other end of the chord connets back to the center of the circle, forming a triangle that looks ALMOST like a rt, triangle, but its not. An arc with a measument of 86 deg. connects the end of the chord that is NOT my radius to the end of the diagonal that is NOT the radius labeled x. \r<BR>\n" );
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document.write( "I figured that the angle of my triangle with its vertex as the circle center is 94 degrees since its complimentary angle is 86 degrees. If I draw a radius that is perpendicular to the chord, the angle (by circle center) would be 47 degrees, right? The angle on the circumference where x connects would be 43 degrees, and the leg of my rt. triangle I created w the radius would be 10 in. I just don't get how to solve for x. And I am worried my reasoning is wrong. Please can you walk me through this problem?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #208423 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=208423\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I think you have to have at least 1 dimension here to find x; the length of the<BR>\n" );
document.write( "chord or the length of the line from the center that bisects the chord. Also I<BR>\n" );
document.write( "think you mean \"...since it's supplementary angle is 86 degrees.\"<BR>\n" );
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document.write( "Your reasoning is correct as far as I understand it  </SPAN>\n" );
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